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>TheSussman New page: <math>\frac{4}{3+x}+\frac{1}{3+x}+\frac{x}{3+x} &=& \frac{7}{18}</math> |
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<math>\frac{4}{3+x}+\frac{1}{3+x}+\frac{x}{3+x} &=& \frac{7}{18}</math> | <math>\frac{4}{3+x}+\frac{1}{3+x}+\frac{x}{3+x} &=& \frac{7}{18}</math> | ||
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Latest revision as of 13:35, 9 December 2024
<math>\frac{4}{3+x}+\frac{1}{3+x}+\frac{x}{3+x} &=& \frac{7}{18}</math>
