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Revision as of 21:01, 18 October 2008 by >TheSussman (New page: <math>\frac{4}{3+x}+\frac{1}{3+x}+\frac{x}{3+x} &=& \frac{7}{18}</math>)
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<math>\frac{4}{3+x}+\frac{1}{3+x}+\frac{x}{3+x} &=& \frac{7}{18}</math>